jQuery : 양식 입력 지우기

jQuery : 양식 입력 지우기

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양식을 지우는 다른 방법을 시도했습니다.

<form action="service.php" id="addRunner" name="addRunner" method="post">
First Name: <input type="text" name="txtFirstName" id="txtFirstName" /><br />
Last Name:  <input type="text" name="txtLastName" id="txtLastName" /><br />
Gender: <select id="ddlGender" name="ddlGender"><option value="">--Please Select--</option>
<option value="f">Female</option>
<option value="m">Male</option>
</select><br />
Finish Time:
<input type="text" name="txtMinutes" id="txtMinutes" size="10" maxlength="2">(Minutes)
<input type="text" name="txtSeconds" id="txtSeconds" size="10" maxlength="2">(Seconds)
<br />
<button type="submit" name="btnSave" id="btnSave">Add Runner</button>
<input type="hidden" name="action" value="addRunner" id="action">
</form>

jQuery # 1 :

function clearInputs(){
$("#txtFirstName").val('');
$("#txtLastName").val('');
$("#ddlGender").val('');
$("#txtMinutes").val('');
$("#txtSeconds").val('');
}

이것은 완벽하게 작동합니다.

jQuery # 2 :

function clearInputs(data){
$("#addRunner :input").each(function(){
$(this).val('');
});

이렇게하면 양식이 지워지지 만 더 이상 정보를 제출할 수 없습니다. 버튼을 다시 클릭하려고했지만 아무 동작도하지 않습니다.

다음은 버튼 클릭 핸들러입니다.

$("#btnSave").click(function(){
    var data = $("#addRunner :input").serializeArray();
    $.post($("#addRunner").attr('action'), data, function(json){
        if (json.status == "fail"){
            alert(json.message);
        }
        if (json.status == "success"){
            alert(json.message);
            clearInputs();
        }
    }, "json");
});

PHP 포스트 코드 :

<?php
if($_POST){ 
    if ($_POST['action'] == 'addRunner') {
        $fname = htmlspecialchars($_POST['txtFirstName']);
        $lname = htmlspecialchars($_POST['txtLastName']);
        $gender = htmlspecialchars($_POST['ddlGender']);
        $minutes = htmlspecialchars($_POST['txtMinutes']);
        $seconds = htmlspecialchars($_POST['txtSeconds']);
        if(preg_match('/[^\w\s]/i', $fname) || preg_match('/[^\w\s]/i', $lname)) {
            fail('Invalid name provided.');
        }
        if( empty($fname) || empty($lname) ) {
                fail('Please enter a first and last name.');
        }
        if( empty($gender) ) {
            fail('Please select a gender.');
        }
        if( empty($minutes) || empty($seconds) ) {
            fail('Please enter minutes and seconds.');
        }
        $time = $minutes.":".$seconds;

    $query = "INSERT INTO runners SET first_name='$fname', last_name='$lname', gender='$gender', finish_time='$time'";
    $result = db_connection($query);

    if ($result) {
        $msg = "Runner: ".$fname." ".$lname." added successfully" ;
        success($msg);
    } else {
        fail('Insert failed.');
    }
    exit;
}

}

jQuery 메서드 # 2를 사용하면 콘솔에 다음 오류가 표시됩니다.

Uncaught TypeError: Cannot read property 'status' of null

왜 이런 일이 발생합니까?

다음 주요 정보를 포함하는 것을 잊었습니다.

function fail ($message){
    die(json_encode(array('status'=>'fail', 'message'=>$message)));
}

function success ($message){
    die(json_encode(array('status'=>'success', 'message'=>$message)));

그러면 jQuery의 AJAX 함수로 메시지가 다시 전송됩니다. 방법 # 2를 사용하여 양식을 한 번 제출하면 성공 / 실패 메시지가 비워진 것 같습니다.

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데모 : http://jsfiddle.net/xavi3r/D3prt/

$(':input','#myform')
  .not(':button, :submit, :reset, :hidden')
  .val('')
  .removeAttr('checked')
  .removeAttr('selected');

원래 답변 : jQuery로 다단계 양식 재설정

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Mike의 제안 (댓글에서) 확인란을 유지하고 그대로 선택합니다!

Warning: If you're creating elements (so they're not in the dom), replace :hidden with [type=hidden] or all fields will be ignored!

$(':input','#myform')
  .removeAttr('checked')
  .removeAttr('selected')
  .not(':button, :submit, :reset, :hidden, :radio, :checkbox')
  .val('');

---

I'd recomment using good old javascript:

document.getElementById("addRunner").reset();

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Took some searching and reading to find a method that suited my situation, on form submit, run ajax to a remote php script, on success/failure inform user, on complete clear the form.

I had some default values, all other methods involved .val('') thereby not resetting but clearing the form.

I got this too work by adding a reset button to the form, which had an id of myform:

$("#myform > input[type=reset]").trigger('click');

This for me had the correct outcome on resetting the form, oh and dont forget the

event.preventDefault();

to stop the form submitting in browser, like I did :).

Regards

Jacko

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You may try

$("#addRunner input").each(function(){ ... });

Inputs are no selectors, so you do not need the : Haven't tested it with your code. Just a fast guess!

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I figured out what it was! When I cleared the fields using the each() method, it also cleared the hidden field which the php needed to run:

if ($_POST['action'] == 'addRunner') 

I used the :not() on the selection to stop it from clearing the hidden field.

참고URL : https://stackoverflow.com/questions/7792320/jquery-clearing-form-inputs